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2y^2-11y-7=0
a = 2; b = -11; c = -7;
Δ = b2-4ac
Δ = -112-4·2·(-7)
Δ = 177
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-\sqrt{177}}{2*2}=\frac{11-\sqrt{177}}{4} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+\sqrt{177}}{2*2}=\frac{11+\sqrt{177}}{4} $
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